f(x)=ax+b jika f (3)= 10 dan f(-1)=2tentukan f(5)
Matematika
aku539
Pertanyaan
f(x)=ax+b jika f (3)= 10 dan f(-1)=2tentukan f(5)
1 Jawaban
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1. Jawaban yourvin
- Fungsi -
f(x) = ax + b
f(3) = 3a + b
10 = 3a + b
b = 10 - 3a
f(-1) = -a + b
2 = -a + (10 - 3a)
2 = -a-3a +10
-8 = -4a
a = 2
b = 10 - 3(2)
b = 10 - 6
b = 4
f(x) = 2x + 4
f(5) = 2(5) + 4 = 10 + 4 = 14
semoga membantu
-vin