persamaan garis lurus melalui titik A(-2,5) dan sejajar garis 3y-4x-8=0 adalah....

jawab
persamaan garris

garis 3y - 4x -8 = 0
3y = 4x + 8
m = 4/3

garis sejajar  m = 4/3 melalui (- 2, 5)
y -y1 = m(x - x1)
y - 5 = 4/3 (x  - (-2))
y - 5 = 4/3 (x + 2)
3(y - 5) = 4(x +2)
3y -15 = 4x + 8
3y = 4x +8 +15
3y = 4x + 23
atau
3y - 4x - 23 = 0