X1,x2,x3 merupakan akar akar persamaan x^3+n= 3x^2+x. Jika x1= -x2, maka x1x2x3 adalah

jawab

suku banyak

x³ - 3x² -x + n = 0
a= 1
b = -3
c = -1
d= n

x1 = - x2  --> x1 + x2= 0
x1 + x2 + x3 = - b/a = 3
0 + x3 = 3
x3 = 3

x1.x2 + x1.x3 + x2.x3 = c/a = -1
x1. x2 + x1 (3) + x2(3) = - 1
x1. x2 + 3 (x1 + x2) =  -1
x1. x2  + 3(0) = - 1
x1. x2 = -1

x1.x2. x3 = (-1)(3) = - 3