diketahui fungsi-fungsi f(x)=2x ,g(x)=x²-1 dan h(x)=2² maka

g(x) = x - 2 => g(h(x)) = h(x) - 2
f(x) = 2x + 1 => f(g(h(x))) = 2g(h(x)) + 1 = 2(h(x) - 2) = 2h(x) - 4

Karena h(x) = x² + 1, maka
f(g(h(x))) = 2h(x) - 4 = 2(x² + 1) - 4 = 2x² - 2.

Dengan demikian, jika f(g(h(x))) = 1, maka
f(g(h(x))) = 1
<=> 2x² - 2 = 1
<=> 2x² = 3
<=> x² = 3/2
<=> x = -√[3/2] atau x = √[3/2]

maaf kalau salah