panjang AB= 12cm , AD=4cm, DE= 8cm, CE=10cm. hitunglah panjang CD dan BE

Ini mencari EB : [tex] \frac{DE}{AB} = \frac{CE}{CB} \\ \frac{8}{12} = \frac{10}{EB+10} \\ \frac{1}{3} = \frac{5}{EB+10} \\ EB+10 = 15 \\ EB = 15-10 \\ EB = 5[/tex]

Ini mencari CD : [tex] \frac{DE}{AB} = \frac{CD}{CD+4} \\ \frac{8}{12} = \frac{CD}{CD+4} \\ \frac{2}{3} = \frac{CD}{CD+4} \\ 2CD + 8 = 3CD \\ 8 = 3CD - 2CD \\ CD = 8[/tex]