Deret geometri (2x-5),(x-4),(-3x+10) tent.x

jawab
deret geo

u1= 2x-5
u2 = x- 4
u3 = -3x + 10

u1 . u3 = u2^2
(2x - 5)(- 3x +10) = ( x- 4)^2
-6x² + 35x - 50 = x ^2 - 8x + 16
- 7x²  + 43x - 66= 0
7x²   - 43 x + 66 = 0
(7x  - 22)(x - 3) = 0

x = 22/7  atau x = 3