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Kelas 11 Matematika
Bab Limit

1] lim ((x - 2) - √(x² - 2)
    x→∞

= lim (√(x² - 4x + 4) - √(x² - 2))
   x→∞

a = 1; b = -4; c = 4; p = 1; q = 0; r = -2

Karena a = p = 1, maka

(b - q)/(2√a)
= (-4 - 0)/(2 . √1)
= -4/2
= -2

2] lim (√(x² - 2x + 3) - (x + 4))
    x→∞

= lim (√(x² - 2x + 3) - √(x² + 8x + 16))
   x→∞

a = 1; b = -2; c = 3; p = 1; q = 8; r = 16

Karena a = p = 1, maka
(b - q)/(2√a)
= (-2 -8)/(2 . √1)
= -10/2
= -5