simpangan baku dari data 3,7,6,6,4,4,2,8 jelaskan jalan nya

jawab
statistik
xi = 3,7,6,6,4,4,2,8
n = 8
∑xi = 40
X= 40/8 =  5
S² = ∑(x-xi)²/n
S² = {(3-5)²+(7-5)²+2(6-5)²+2(4-5)²+ (2-5)²+(8-5)²}/ (8)
S² = (4  + 4 + 2 + 2+ 9+ 9)/ (8) = 30/8

simpangan baku s = √s²  = √(30/8)= 1.94