jika f(2x+1)=4x-3 dan h(x)=√x hitung foh (4)

- Fungsi Komposisi -

f(2x+1) = 4x-3
misalkan, u = 2x+1 -> x = (u-1)/2
f(u) = 4(u-1)/2 - 3
f(u) = 2u-2-3
f(u) = 2u-5
f(x) = 2x-5

(foh)(x) = 2√x - 5
(foh)(4) = 2√4 - 5
(foh)(4) = 2.2 - 5 = 4 - 5 = -1

semoga membantu
-vin