Diketahui (f o g)(x)=4x^2-12x+5. Tentukan : a. g(x) jika f(x)=2x-1 b. f(x) jika g(x)=2x-1

a. g(x) = (f o g) (x) = 4x²-12x+5
<=> f(g(x)) = 4x²-12x+5
2 g(x) -1 = 4x²-12x+5
2 g(x) = 4x²-12x+5+1
g(x) = 4x²-12x+5-1
________
2
= 2x²-6x+3
jadi, rumus fungsi g(x) = 2x²-6x+3
b. f(x) = (f o g)(x) = 4x²-12x+5
f(g(x)) = 4x²-12x+5
f(2x-1) = 4x²-12x+5
misalkan = 2x-1 = a, maka 2x = a-1 atau x = a-1
__
2
f(a) = 4(a-1)²+12(a-1)+5
__ __
2 2
= 4(a²-2a+2)+6a-6+5
______
2
= a²-2a+2+6a-1
f(a) = a²-4a+1
jadi, rumus fungsi f(x) = x²-4x+1

insyaallah itu jwbannya