Matematika

Pertanyaan

Akar2 persamaan kuadrat 2×2+mx+16=0 adalah a dan b jika a,b positif nilai m yg memenuhi adalah

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    x1 = a = 2
    x2 = b = m
    c = 16

    x1 + x2 = -b/a = -m/2
    a + b = -m/2

    x1.x2 = c/a = 16/2 = 8
    a.b = 8

    a = 2b --> a.b = 8
    2b.b = 8
    b^2 = 8/2
    b^2 = 4
    b = 2
    a = 2b = 2.2 = 4

    a+b = -m/2
    4+2 = -m/2
    6 = -m/2
    -m = 6 × 2
    -m = 12
    m = -12

    semoga membantu

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