6√8−4√32+√128 adalah?

- Operasi Bentuk Akar -

6√8 - 4√32 + √128
= 6√(4.2) - 4√(16.2) + √(64.2)
= 12√2 - 16√2 + 8√2
= (12-16+8)√2
= 4√2

semoga membantu
-vin

Penyelesaian :

[tex]6 \sqrt{8} - 4 \sqrt{32} + \sqrt{128} \\ = 6 \sqrt{4 \times 2} - 4\sqrt{16 \times 2} + \sqrt{64 \times 2} \\ = 12 \sqrt{2} - 16 \sqrt{2} + 8 \sqrt{2} \\ = (12 - 16 + 8) \sqrt{2} \\ = 4 \sqrt{2} [/tex]

- MathLovers♡