Jika x_{1} dan x_{2} penyelesaian persamaan 3^{x^2-3} = 27^{x-5} , maka x_{1} + x_{2} =

3^(x^2-3)) = 27^(x-5)
3^(x^2 -3) = (3^3)^(x-5)
3^(x^2-3) = 3^(3x-15)
x^2 -3 = 3x -15
x^2 -3x + 12 = 0
x1 + x2 = - -3/1
= 3/1
= 3