Banyaknya lilitan sekunder trafo=3x lilitan primer. Bila besar kuat arus primer 6A berapakah kuat arus sekunder?

INDUKSI ELEKTROMAGNETIK
• transformator

transformator ideal
Nₛ = 3 Nₚ
iₚ = 6 A
iₛ = ___?

Nₚ / Nₛ = iₛ / iₚ
Nₚ / (3 Nₚ) = iₛ / 6
⅓ = iₛ / 6
iₛ = ⅓ × 6
iₛ = 2 A ✔️

kuat arus sekunder 2 A

Kuat Arus = I
Lilitan = N

Diketahui perbandingannya
Ns = 3Np
Maka Ns = 3 sedangkan Np = 1

Rumus
Is = Np x Ip ÷ Ns
Is = 1 x 6A ÷ 3
Is = 6A ÷ 3
Is = 2A