Matematika

Pertanyaan

1. 19per20 + 6per15 =
2. 26per8 + 12per8 =
3. 1per3 + 6per15 =
4. 4 4per10 + 3per4 =
5. 6per12 - 3per12 =

tolong dibantu ya kaka-kaka

2 Jawaban

  • 1.
    [tex] = \frac{19}{20} + \frac{6}{15} \\ = \frac{285 + 120}{300} \\ = \frac{405}{300} \\ = \frac{81}{60} [/tex]
    2.
    [tex] = \frac{26}{8} + \frac{12}{8} \\ = \frac{26 + 12}{8} \\ = \frac{40}{8} \\ = 5[/tex]
    3.
    [tex] = \frac{1}{3} + \frac{6}{15} \\ = \frac{5 + 6}{15} \\ = \frac{11}{15} [/tex]
    4.
    [tex] = 4 \frac{4}{10} + \frac{3}{4} \\ = \frac{44}{10} + \frac{3}{4} \\ = \frac{22}{5} + \frac{3}{4} \\ = \frac{88 + 15}{20} \\ = \frac{103 }{20} [/tex]

  • 1. 19/20 + 6/15 = 57/60 + 24/60 = (57+24)/60= 81/60
    2. 26/8 + 12/8 = (26+12)/8 = 38/8
    3. 1/3 + 6/15 = 5/15 + 6/15 = 11/15
    4. 4/10 + 3/4 = 16/40 + 30/40 = (16+30)/40 = 46/40
    5. 6/12 - 3/12 = (6-3)/12 = 3/12

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