Akar persamaan kuadrat 2x^2+mx+16=0 adalah a dan B. Jika a =2B dan a, B positif, nilai m yabg memenuhi?

[tex]2x {}^{2} + mx + 16[/tex]
[tex]a = 2b[/tex]


x1 = a = 2
x2 = b = m
c = 16

x1 + x2 = -b/a = -m/2
a + b = -m/2

x1.x2 = c/a = 16/2 = 8
a.b = 8

a = 2b --> a.b = 8
2b.b = 8
b^2 = 8/2
b^2 = 4
b = 2
a = 2b = 2.2 = 4

a+b = -m/2
4+2 = -m/2
6 = -m/2
-m = 6 × 2
-m = 12
m = -12
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