Nilai dari (125) 2/3 - (16) 3/4 per (9) 3/2 + (32) 3/5

jawab
bilangan berpangkat

{ 125^(2/3) - 16)^(3/4) } / {9^(3/2) - 32^(3/5) =

= ( 5^3(2/3) - 2^4(3/4)  / { 3^2(3/2) - 2^5(3/5) }

= ( 5^2 - 2^3) / (3^3 - 2^3)

= (25 -8) /(27 -8)

= 17/19