tolong di bantu beserta caranya. besok di kumpul kan

Maple : Matematika

Soal No. 9
Materi : Baris dan Deret - Aritmatika
[tex]S_n= \frac{n}{2}(2a+(n-1).b)\\\\S_{10}=\frac{10}{2}(2(20)+(10-1).4)\\\\S_{10}=5\times(40+(9\times4))\\\\S_{10}=5\times(40+36)\\\\S_{10}=5\times76\\\\\boxed{S_{10}=380}...........Jawaban\ (B)[/tex]

Soal No. 10
Materi : Faktorisasi Persamaan Kuadrat
[tex]=2a^2-72\\\\=2(a^2-36)...................a^2-b^2=(a+b)(a-b)\\\\=2(a^2-6^2)\\\\=2(a+6)(a-6).................Jawaban\ (C)[/tex]

Soal No. 11
Materi : Himpunan Pertidaksamaan
-3x - 4 ≥ -4x + 10
4x - 3x ≥ 10 + 4
x ≥ 14
x = {14, 15, 16,...}....................Jawaban (A)

Soal No. 12
Materi : Bangun Datar - Persegi Panjang
Keliling = 2 (Panjang + Lebar)
41 = 2 (12,5 + Lebar)
41 = 25 + 2(Lebar)
Lebar = (41 - 25) ÷ 2
Lebar = 16 ÷ 2
Lebar = 8 cm

Luas = Panjang × Lebar
Luas = 12,5 × 8
Luas = 100 cm².....................Jawaban (B)

Soal No. 13
Materi : Himpunan
A = {7, 11, 13, 17, 19, 23, 29}
B = {7, 11, 13, 17}

A - B = (A ∪ B) - B
A - B = {19, 23, 29}.......................Jawaban (D)

Soal No. 14
Materi : Himpunan
Diketahui :
S = 140
n(Sb) = 90
n(Bs) = 87
n( Sb ∩ Bs) = 60

Ditanya :
Siswa tidak gemar keduanya

Jawab :
 
[tex]n(Sb\cup Bs)=n(Sb)+n(Bs)-n(Sb\cap Bs)\\n(Sb\cup Bs)=90+87-60\\n(Sb\cup Bs)=177-60\\n(Sb\cup Bs)=117\\\\n(Sb\cup Bs)^{\complement}=n(S)-n(Sb\cup Bs)\\n(Sb\cup Bs)^{\complement}=140-117\\\bold{n(Sb\cup Bs)^{\complement}=23\ \text{orang}}.................\text{Jawaban (B)}[/tex]

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